Math // Measurement
Perimeter (age 10+)
Recognise that shapes with the same area can have different perimeters and vice versa; explore this relationship systematically
Quick check
If the learner has 12 square tiles to arrange, can they make different-shaped rectangles and notice that the area stays the same (12 tiles) but the perimeters are all different?
Ask this to see whether the topic is secure.
Topic // Mastery
What mastery looks like
- Draw two rectangles with area 24 cm² but different perimeters
- Find two shapes with perimeter 20 cm but different areas
- Explain why a long thin rectangle and a square can have the same area but different perimeters
Topic // Map
Where this fits
- RequiredMust come first
- HelpfulHelps, but not essential
Before this
1 topic- Estimating answers (age 9+)Required
Measurement // Ages 9 to 10
Exploring area/perimeter relationship requires area and perimeter formula knowledge
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Perimeter (age 10+)
Ages 10 to 11 // Concept
Leads to
0 topicsNothing in the catalogue builds on this topic yet. Browse Measurement
Topic // Research-informed
Teaching notes
From the Marble Skill Taxonomy. These notes have not been validated in classrooms, so treat them as a starting point for your own judgement.
The approach
Children learn that knowing one of area or perimeter does NOT determine the other: two shapes can share an area yet have different perimeters, and share a perimeter yet have different areas. (They are not completely unrelated, though: for example, a fixed perimeter limits how large the area can be.) The core work is systematic — fix one quantity (e.g. area 24 cm²) and generate shapes that differ in the other, tabulating so the variation is SEEN, not asserted. The target misconception is the intuitive 'Same A – Same B' rule (same area must mean same perimeter, and vice versa). Because a correct answer can come from the faulty intuition, always probe the reasoning.
Common misconceptions
- 'Same A – Same B': believes shapes with equal area must have equal perimeter (or that changing sides by equal-and-opposite amounts leaves both unchanged).
- Conflates area and perimeter, so cannot hold one fixed while varying the other.
- Thinks making a shape 'bigger' must increase area and perimeter together.
Useful representations
- Squared paper / tile arrangements at fixed area
- Table of dimensions versus perimeter (or perimeter versus area)
- Long-thin-versus-square rectangle pair with equal area
- Fence/string model for perimeter around a fixed area
Teaching practices
- Fix one quantity and vary the shape systematically (all rectangles of area 24; all shapes of perimeter 20), tabulating the other so children see it change.
- Confront the 'Same A – Same B' intuition head-on with counterexamples (a 3×4 and a 2×6 rectangle both have area 12 but perimeters 14 and 16).
- Use squared paper and tiles so children construct and count rather than rely on a remembered rule.
- Probe reasoning beyond correct answers — a right answer can come from the intuitive rule, so always ask 'why' (Tsamir & Mandel).
- Link to practical intuition: a long thin field and a square field can hold the same crop area but need very different lengths of fence.
Activities to try
- 1
Lock the area, watch the perimeter change
Why it works: Keeping area fixed while reshaping shows the perimeter climbing even though the covered surface is unchanged, so same area does NOT force same perimeter.
- Start from a 4×6 rectangle on squared paper (or a drag-to-reshape grid) that reads 'Area 24 cm², Perimeter 20 cm'.
- Reshape it to 3×8, 2×12, then 1×24, keeping the area pinned at 24 cm² each time.
- After each shape, count the squares to confirm the area is still 24, then count the edge units to find the new perimeter (20, 22, 28, 50 cm).
- Record each rectangle's dimensions and perimeter in a table so the growing perimeter is visible alongside the unchanged area.
- Say aloud what stays the same and what changes.
- 2
Lock the perimeter, watch the area change
Why it works: With perimeter held constant, the area varies — so same perimeter does NOT force same area either; in both directions, fixing one quantity does not fix the other (although the fixed perimeter does cap the area: here the 5×5 square gives the most).
- Fix a perimeter (e.g. 20 cm) and build several rectangles that all have that perimeter: 1×9, 2×8, 3×7, 4×6, 5×5.
- For each, count the squares to find the area (9, 16, 21, 24, 25 cm²) and record it in a table.
- Note which shape gives the largest area and which the smallest for the same perimeter.
- 3
The string test (predict, then check)
Why it works: Both rectangles cover the same area (12 cm²) but their perimeters differ (14 cm and 16 cm) — a direct counterexample to 'Same A – Same B'.
- Look at a 3×4 rectangle and a 2×6 rectangle on squared paper; confirm both have area 12 cm² by counting squares.
- PREDICT whether one loop of string will go exactly around both, and say WHY before testing.
- Lay the string around each and measure: the 3×4 needs 14 cm, the 2×6 needs 16 cm.
- Draw a THIRD rectangle with area 12 but yet another perimeter, and find the largest perimeter you can make for area 12 (with whole-number sides, the thinnest 1×12 gives 26 cm).
Topic // Standards
Curriculum standards
- The national curriculum in England: Key stages 1 and 2 framework document
- Ma6/3.1d
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